Question: A moving train, 66 m long, overtakes another train of 88 m long, moving in the same direction in 0.168 min. If the second train is moving at 30 km/h, at what speed is the first train moving?
Options:
A) 85 km/h
B) 55 km/h
C) 50 km/h
D) 25 km/h
Show Answer
Answer:
Correct Answer: A
Solution:
- Suppose the speed of first train $ =xm/\min . $
Speed of second train = 30 km/h
$ =\frac{30\times 1000}{60}=500,m/\min $
Then, relative speed $ =(x-500)m/\min $
According to the question,
$ Timetaken=\frac{Sumoflengthsoftrain}{Relativespeed} $
$ 0.168=\frac{66+88}{x-500} $
$ \Rightarrow $ $ 0.168x-84=66+88 $
$ \Rightarrow $ $ 0.168x=154+84=238 $
$ \Rightarrow $ $ x=\frac{238}{0.168}m/\min =\frac{238}{0.168}\times \frac{3}{50}\text{km/h} $
$ \Rightarrow $ $ x=85km/h $