Question: When x is subtracted from the numbers 9, 15 and 27, the remainders are in continued proportion. What is the value of x? [IBPS (PO/MT) 2012]
Options:
A) 8
B) 6
C) 4
D) 5
E) None of these
Show Answer
Answer:
Correct Answer: E
Solution:
- $ \frac{9-x}{15-x}=\frac{15-x}{27-x} $
$ \Rightarrow $ $ 243-9x-27x+x^{2}=225-15x-15x+x^{2} $
$ \Rightarrow $ $ 6x=243-225=18 $
$ \Rightarrow $ $ x=3 $