Quantitative Aptitude Ques 958

Question: In how many ways can 10 books be arranged on a shelf, so that two specified books are not together?

Options:

A) $ 9!\times 2 $

B) $ 9!\times 8 $

C) $ 10!\times 2 $

D) $ 9!\times 4 $

Show Answer

Answer:

Correct Answer: B

Solution:

  • Total number of arrangements of 10 books =10! If two specified books are always together, then the number of arrangements $ =9!\times 2! $ Hence, the number of ways in which two specified books are not together $ =10!-9!\times 2! $ $ =10\times 9!-2\times 9!=9!(8) $
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