Question: The external fencing of a circular path around a circular plot of land is 33 m more than its interior fencing. The width of the path around the plot is
Options:
A) 5.52 m
B) 5.25 m
C) 2.55 m
D) 2.25 m
Show Answer
Answer:
Correct Answer: B
Solution:
- Let interior circumference of circular path $ =xm $ and external circumference of circular path $ =(x+33)m $
Now, let internal radius $ =r _1 $
and external radius $ =r _2 $
$ \therefore $ $ x=2\pi r _1 $ and $ (x+33)=2\pi r _2 $
On subtracting these, we get
$ 33=2\pi (r _2-r _1) $
$ \Rightarrow $ $ r _2-r _1=\frac{33}{2\pi }=\frac{33\times 7}{2\times 22}=\frac{21}{4}=5.25m $
Hence, the width of the path $ =r _2-r _15.25m $