SATHEE: Quantitative Aptitude Ques 940

Quantitative Aptitude Ques 940

Question: In a $ \Delta ABC, $ it is given that AD is the internal bisector of $ \angle A. $ If $ AB=10cm, $ $ AC=14cm $ and $ BC=6cm, $ then CD is equal to

Options:

A) $ 4.8cm $

B) $ 3.5cm $

C) $ 7cm $

D) $ 10.5cm $

Show Answer

Answer:

Correct Answer: B

Solution:

Let CD be $ xcm. $ Then, $ BD=(6-x)cm $ Now, $ \frac{BD}{CD}=\frac{AB}{AC} $

$ \Rightarrow $ $ \frac{6-x}{x}=\frac{10}{14}=\frac{5}{7} $

$ \Rightarrow $ $ 42-7x=5x $
$ \Rightarrow $ $ 12x=42 $

$ \therefore $ $ x=3.5 $

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Quantitative Aptitude Ques 940

Question: In a $ \Delta ABC, $ it is given that AD is the internal bisector of $ \angle A. $ If $ AB=10cm, $ $ AC=14cm $ and $ BC=6cm, $ then CD is equal to

Options:

Answer:

Solution:

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