SATHEE: Quantitative Aptitude Ques 931

Quantitative Aptitude Ques 931

Question: Directions: In the following questions, two equations I and II are given. You have to solve both the equation and give answer.

I. $ 5x^{2}-18x+9=0 $ II. $ 3y^{2}+5y-2=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or the relationship cannot be established

Show Answer

Answer:

Correct Answer: A

Solution:

I. $ 5x^{2}-18x+9=0 $

$ \Rightarrow $ $ 5x^{2}-15x-3x+9=0 $

$ \Rightarrow $ $ 5x(x-3)-3(x-3)=0 $

$ \Rightarrow $ $ (5x-3)(x-3)=0 $

$ \Rightarrow $ $ x=3, $ $ \frac{3}{5} $ II. $ 3y^{2}+5y-2=0 $

$ \Rightarrow $ $ 3y^{2}+6y-y-2=0 $

$ \Rightarrow $ $ 3y(y+2)-1(y+2)=0 $

$ \Rightarrow $ $ (3y-1)(y+2)=0 $

$ \Rightarrow $ $ y=-2, $ $ \frac{1}{3} $

$ \therefore $ $ y<x $

Quantitative Aptitude Ques 930

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