Quantitative Aptitude Ques 922

Question: The value of t for which $ m^{2}-\frac{3m}{2}+t $ will be a perfect square, is

Options:

A) $ \frac{9}{4} $

B) $ \frac{9}{16} $

C) $ \frac{3}{2} $

D) $ \frac{3}{4} $

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ m^{2}-\frac{3m}{2}+t={{( m-\frac{3}{4} )}^{2}}+t-\frac{9}{16} $ So, if $ t=\frac{9}{16}, $ it will become a perfect square. Alternate Method Given equation $ =m^{2}-\frac{3m}{2}+t $ Now, taking the standard perfect square $ {{(x-y)}^{2}}=x^{2}+y^{2}-2xy $ On comparing, we get $ m^{2}=x^{2}, $ $ y^{2}=t $ and $ \frac{3}{2}m=2m\sqrt{t} $

$ \Rightarrow $ $ \sqrt{t}=\frac{3}{4} $
$ \Rightarrow $ $ t=\frac{9}{16} $ Hence, value of t should be $ \frac{9}{16} $ to make the given equation a perfect square.