SATHEE: Quantitative Aptitude Ques 920

Quantitative Aptitude Ques 920

Question: The base of a conical tent is 19.2 m in diameter and its height is 2.8 m. The area $ (in{m^{2}}) $ of the canvas required to put up such a tent is nearly (take $ \pi =\frac{22}{7} $ )

Options:

A) 3017.10

B) 3170

C) 301.71

D) 30.17

Show Answer

Answer:

Correct Answer: C

Solution:

Radius of the circular base, $ r=\frac{19.2}{2}=9.6m $ $ h=2.8m $ Slant height, $ l=\sqrt{h^{2}+b^{2}}=\sqrt{{{(2.8)}^{2}}+{{(9.6)}^{2}}} $ $ =\sqrt{7.84+92.16} $ $ =\sqrt{100}=10m $

$ \therefore $ Area of the canvas = Surface area of cone $ =\frac{22}{7}\times 9.6\times 10=301.71m^{2} $

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Quantitative Aptitude Ques 920

Question: The base of a conical tent is 19.2 m in diameter and its height is 2.8 m. The area $ (in{m^{2}}) $ of the canvas required to put up such a tent is nearly (take $ \pi =\frac{22}{7} $ )

Options:

Answer:

Solution:

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