Quantitative Aptitude Ques 880
Question: The number of sides in two regular polygons are as 5 : 4 and difference between their angles is $ 6{}^\circ . $ The number of sides in the polygons are
Options:
A) 12 and 15
B) 12 and 13
C) 20 and 16
D) 15 and 12
Show Answer
Answer:
Correct Answer: D
Solution:
- Let the number of sides of two regular polygons be $ 5x $ and $ 4x, $ respectively.
$ \therefore $ Angle of polygons of sides $ 5x=(2\times 5x-4) $ $ =(10x-4) $ and angle of polygons of sides $ 4x=(2\times 4x-4) $ $ =(8x-4) $ Given that difference of their angles is 6. Then, according to the question, $ (10x-4)-(8x-4)=6 $
$ \Rightarrow $ $ 2x=6 $
$ \Rightarrow $ $ x=3 $
$ \therefore $ Sides of 1st polygon $ =5x=5\times 3=15 $ Sides of 2nd polygon $ =4x=4\times 3=12 $
BETA
