SATHEE: Quantitative Aptitude Ques 880

Quantitative Aptitude Ques 880

Question: The number of sides in two regular polygons are as 5 : 4 and difference between their angles is $ 6{}^\circ . $ The number of sides in the polygons are

Options:

A) 12 and 15

B) 12 and 13

C) 20 and 16

D) 15 and 12

Show Answer

Answer:

Correct Answer: D

Solution:

Let the number of sides of two regular polygons be $ 5x $ and $ 4x, $ respectively.

$ \therefore $ Angle of polygons of sides $ 5x=(2\times 5x-4) $ $ =(10x-4) $ and angle of polygons of sides $ 4x=(2\times 4x-4) $ $ =(8x-4) $ Given that difference of their angles is 6. Then, according to the question, $ (10x-4)-(8x-4)=6 $

$ \Rightarrow $ $ 2x=6 $
$ \Rightarrow $ $ x=3 $

$ \therefore $ Sides of 1st polygon $ =5x=5\times 3=15 $ Sides of 2nd polygon $ =4x=4\times 3=12 $

Quantitative Aptitude Ques 879

Quantitative Aptitude Ques 881

Quantitative Aptitude Ques 880

Question: The number of sides in two regular polygons are as 5 : 4 and difference between their angles is $ 6{}^\circ . $ The number of sides in the polygons are

Options:

Answer:

Solution:

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