Question: If the points $ (x+1,2), $ $ (1,x+2), $ $ ( \frac{1}{x+1},\frac{2}{x+1} ) $ are collinear, then x is
Options:
A) $ 4 $
B) 5
C) $ -4 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- Since, the points are collinear.
Hence, there slopes are equal.
Now, $ \frac{(x+2)-2}{1-(x+1)}=\frac{( \frac{2}{x+1} )-(x+2)}{( \frac{1}{x+1} )-1} $
$ \Rightarrow $ $ -1=\frac{2-(x^{2}+3x+2)}{1-(x+1)} $
$ \Rightarrow $ $ x=-4 $