Quantitative Aptitude Ques 873

Question: There is 81 L pure milk in a container. One-third of milk is replaced by water in the container. Again, one-third of mixture is extracted and equal amount of water is added. What is the ratio of milk to water in the new mixture?

Options:

A) 1 : 2

B) 1 : 1

C) 2 : 1

D) 4 : 5

Show Answer

Answer:

Correct Answer: D

Solution:

  • Given, pure milk in container $ =81L $ By replacing $ \frac{1}{3} $ part by water, Remaining milk $ 81-\frac{1}{3}\times 81=81-27=54L $ Again, replacing $ \frac{1}{3} $ part by water.

$ \therefore $ Remaining milk $ =54-\frac{1}{3}\times 54=54-18=36L $ Then, quantity of water at last $ =81-36=45L $

$ \therefore $ Required ratio $ =\frac{36}{45}=\frac{4}{5} $