Question: There is 81 L pure milk in a container. One-third of milk is replaced by water in the container. Again, one-third of mixture is extracted and equal amount of water is added. What is the ratio of milk to water in the new mixture?
Options:
A) 1 : 2
B) 1 : 1
C) 2 : 1
D) 4 : 5
Show Answer
Answer:
Correct Answer: D
Solution:
- Given, pure milk in container $ =81L $
By replacing $ \frac{1}{3} $ part by water,
Remaining milk $ 81-\frac{1}{3}\times 81=81-27=54L $
Again, replacing $ \frac{1}{3} $ part by water.
$ \therefore $ Remaining milk $ =54-\frac{1}{3}\times 54=54-18=36L $
Then, quantity of water at last $ =81-36=45L $
$ \therefore $ Required ratio $ =\frac{36}{45}=\frac{4}{5} $