A) $ \frac{1}{2}kg $
B) $ \frac{1}{8}kg $
C) $ \frac{3}{14}kg $
D) $ \frac{7}{9}kg $
Correct Answer: B
$ \therefore $ Quantity of lead in $ 1kg $ of second alloy $ =\frac{3}{12}=\frac{1}{4}kg $
$ \therefore $ Quantity of lead in $ 2kg $ of new alloy $ =\frac{1}{4}+0=\frac{1}{4}kg $
$ \therefore $ Quantity of lead in $ 1kg $ of new alloy $ =\frac{1}{8}kg $