Question: The simple interest accrued on an amount of Rs. 20000 at the end of 3 yr is Rs. 7200. What would be the compound interest accrued on the same amount at the same rate in the same period?
Options:
A) Rs. 8342.36
B) Rs. 8098.56
C) Rs. 8246.16
D) Rs. 8112.86
E) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- $ Rate=\frac{SI\times 100}{Principal\times Time}=\frac{7200\times 100}{20000\times 3}=12 $ %
$ \therefore $ $ CI=P[ {{( 1+\frac{R}{100} )}^{T}}-1 ] $
$ =20000[ {{( 1+\frac{12}{100} )}^{3}}-1 ] $
$ =20000[{{(1.12)}^{3}}-1] $
$ =20000,[1.404928-1]=Rs\text{.}8098\text{.56} $