Quantitative Aptitude Ques 869

Question: The simple interest accrued on an amount of Rs. 20000 at the end of 3 yr is Rs. 7200. What would be the compound interest accrued on the same amount at the same rate in the same period?

Options:

A) Rs. 8342.36

B) Rs. 8098.56

C) Rs. 8246.16

D) Rs. 8112.86

E) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ Rate=\frac{SI\times 100}{Principal\times Time}=\frac{7200\times 100}{20000\times 3}=12 $ %

$ \therefore $ $ CI=P[ {{( 1+\frac{R}{100} )}^{T}}-1 ] $ $ =20000[ {{( 1+\frac{12}{100} )}^{3}}-1 ] $ $ =20000[{{(1.12)}^{3}}-1] $ $ =20000,[1.404928-1]=Rs\text{.}8098\text{.56} $