Question: A pipe can fill a tank in x h and another pipe can empty it in $ y(y>x)h. $ If both the pipes are open, in how many hours will the tank be filled?
Options:
A) $ (x-y) $
B) $ (y-x) $
C) $ \frac{xy}{x-y} $
D) $ \frac{xy}{y-x} $
Show Answer
Answer:
Correct Answer: D
Solution:
- Part of the tank filled in, $ 1h=\frac{1}{x} $
Part at the tank emptied in $ 1h=\frac{1}{y} $
Part of the tank filled in 1 h when both are opened
$ =\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy} $
$ \therefore $ Tank will be filled in $ \frac{xy}{y-x}h. $