SATHEE: Quantitative Aptitude Ques 830

Quantitative Aptitude Ques 830

Question: In AB = 5 cm, AC = 12 cm and $ AB\bot AC, $ then the radius of the circumcircle of $ \Delta ABC $ is

Options:

A) 6.5 cm

B) 6 cm

C) 5 cm

D) 7 cm

Show Answer

Answer:

Correct Answer: A

Solution:

Given, $ \Delta ABC $ with $ AB=5cm, $ $ AC=12cm $ and $ AB\bot AC $ Since, $ \angle BAC=90{}^\circ $ So, BC is the diameter of the circle,[by property of semi-circle] $ {{\text{(Hypotentuse)}}^{2}}\text{+(Perpendicular}{{)}^{2}}\text{+(Base}{{)}^{2}} $ We have, $ BC^{2}=AB^{2}+AC^{2} $

$ \Rightarrow $ $ BC^{2}=5^{2}+12^{2}=25+144=169 $

$ \therefore $ $ BC=13cm $

$ \Rightarrow $ Radius $ =\frac{BC}{2}=6.5,cm $

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Quantitative Aptitude Ques 830

Question: In AB = 5 cm, AC = 12 cm and $ AB\bot AC, $ then the radius of the circumcircle of $ \Delta ABC $ is

Options:

Answer:

Solution:

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