Quantitative Aptitude Ques 807

Question: The arrangement of rational numbers $ \frac{-7}{10}, $ $ \frac{5}{-8}, $ $ \frac{2}{-3} $ in ascending order is

Options:

A) $ \frac{2}{-3}<\frac{5}{-8}<\frac{-7}{10} $

B) $ \frac{5}{-8}<\frac{-7}{10}<\frac{-2}{3} $

C) $ \frac{-,7}{10}<\frac{5}{-8}<\frac{2}{-3} $

D) $ \frac{-7}{10}<\frac{2}{-3}<\frac{5}{-8} $

Show Answer

Answer:

Correct Answer: D

Solution:

  • LCM of 10, 8, 3 = 240 $ \frac{-7}{10}=\frac{168}{240} $
    $ \Rightarrow $ $ \frac{-5}{8}=\frac{-150}{240} $ $ \frac{-2}{3}=\frac{-160}{240} $ Since, $ \frac{-168}{240}<\frac{-160}{240}<\frac{-150}{240} $

$ \therefore $ $ \frac{-7}{10}<\frac{-2}{3}<\frac{-5}{8} $

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