Question: The digit in unit’s place of the number $ {{(1570)}^{2}}+{{(1571)}^{2}}+{{(1572)}^{2}}+{{(1573)}^{2}} $ is
Options:
A) 4
B) 2
C) 1
D) 3
Show Answer
Answer:
Correct Answer: A
Solution:
- Unit digit of $ {{(1570)}^{2}}=0 $
Unit digit of $ {{(1571)}^{2}}=1 $
Unit digit of $ {{(1572)}^{2}}=4 $
Unit digit of $ {{(1573)}^{2}}=9 $
Required unit digit = Unit digit of
$ (0+1+4+9)=14 $
$ \therefore $ Unit digit = 4