Quantitative Aptitude Ques 80
Question: Directions: In each of the following questions two equations I and II are given. You have to solve both the equations and find out values of x, y and give answer. [LIC (AAO) 2014]
I. $ \sqrt{(36)}x+\sqrt{64}=0 $
II. $ \sqrt{(81)}y+{{(4)}^{2}}=0 $
Options:
A) If $ x>y $
B) If $ x\le y $
C) If $ x<y $
D) If $ x\ge y $
E) If relationship cannot be established
Show Answer
Answer:
Correct Answer: A
Solution:
- I. $ \sqrt{36}x+\sqrt{64}=0 $
$ \Rightarrow $ $ 6x+8=0 $
$ \Rightarrow $ $ x=\frac{-,8}{6} $
$ \Rightarrow $ $ x=\frac{-,4}{3} $
II. $ \sqrt{81}y+4^{2}=0 $
$ \Rightarrow $ $ 9y+16=0 $
$ \Rightarrow $ $ y=\frac{-16}{9} $
Hence, $ x>y $