Quantitative Aptitude Ques 80

Question: Directions: In each of the following questions two equations I and II are given. You have to solve both the equations and find out values of x, y and give answer. [LIC (AAO) 2014]

I. $ \sqrt{(36)}x+\sqrt{64}=0 $
II. $ \sqrt{(81)}y+{{(4)}^{2}}=0 $

Options:

A) If $ x>y $

B) If $ x\le y $

C) If $ x<y $

D) If $ x\ge y $

E) If relationship cannot be established

Show Answer

Answer:

Correct Answer: A

Solution:

  • I. $ \sqrt{36}x+\sqrt{64}=0 $

$ \Rightarrow $ $ 6x+8=0 $

$ \Rightarrow $ $ x=\frac{-,8}{6} $
$ \Rightarrow $ $ x=\frac{-,4}{3} $ II. $ \sqrt{81}y+4^{2}=0 $

$ \Rightarrow $ $ 9y+16=0 $
$ \Rightarrow $ $ y=\frac{-16}{9} $ Hence, $ x>y $