Question: 50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is $ 4m^{3}, $ then the rise in value level
Options:
A) 20 cm
B) 35 cm
C) 25 cm
D) 50 cm
Show Answer
Answer:
Correct Answer: C
Solution:
- Total volume of water displaced
$ =(4\times 50)m^{3}=200m^{3} $
$ \therefore $ Rise in water level $ =( \frac{200}{40\times 20} )m=0.25m=25cm $