Question: A 180 m long train crosses another 270 m long train running in the opposite direction in 10.8 s. If the speed of the first train is 60 km/h then what is the speed (in km/h) of the second train?
Options:
A) 80
B) 90
C) 150
D) Cannot be determined
E) None of the above
Show Answer
Answer:
Correct Answer: B
Solution:
- Time taken by trains in, crossing each other
$ \text{=}\frac{Sumoflengthsoftrains}{Relativespeed} $
Also, $ 60km/h=\frac{60\times 5}{18}=\frac{50}{3}m/s $
If the speed of second train be x m/s, then
$ 10.8=\frac{180+270}{\frac{50}{3}+x} $
$ \Rightarrow $ $ 10.8( \frac{50}{3}+x )=450 $
$ \Rightarrow $ $ 180+10.8x=450 $
$ \Rightarrow $ $ 10.8x=450-180=270 $
$ \Rightarrow $ $ x=\frac{270}{10.8}=25m/s $
$ =25\times \frac{18}{5}km/h=90km/h $