SATHEE: Quantitative Aptitude Ques 782

Quantitative Aptitude Ques 782

Question: Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.

I. $ {{(17)}^{2}}+114\div 18=x $
II. $ {{(26)}^{2}}-18\times 21=y $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or the relationship cannot be established

Show Answer

Answer:

Correct Answer: C

Solution:

I. $ {{(17)}^{2}}+114\cdot 18=x $

$ \Rightarrow $ $ 17^{2}+\frac{114}{18}=x $

$ \Rightarrow $ $ 289+6.33=x $

$ \Rightarrow $ $ 295.33=x $ II. $ {{(26)}^{2}}-18\times 21=y $

$ \Rightarrow $ $ 676-378=y $
$ \Rightarrow $ $ 298=y $

$ \therefore $ $ y>x $

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Quantitative Aptitude Ques 782

Question: Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.

Options:

Answer:

Solution:

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