SATHEE: Quantitative Aptitude Ques 767

Quantitative Aptitude Ques 767

Question: The numerator of a fraction is 4 less than its denominator. If the numerator is decreased by 2 and the denominator is increased by 1, then the denominator becomes eight times the numerator. Find the fraction.

Options:

A) $ \frac{3}{7} $

B) $ \frac{4}{7} $

C) $ \frac{5}{7} $

D) $ \frac{6}{7} $

Show Answer

Answer:

Correct Answer: A

Solution:

Let denominator of fraction $ =x $ Then, numerator $ =x-4 $

$ \therefore $ Fraction $ =\frac{x-4}{x} $ According to the question, $ \frac{(x-4)-2}{x+1}=\frac{1}{8} $

$ \Rightarrow $ $ x-6=\frac{x+1}{8} $

$ \Rightarrow $ $ 8x-48=x+1 $

$ \Rightarrow $ $ 8x-x=48+1 $

$ \Rightarrow $ $ 7x=49 $
$ \Rightarrow $ $ x=7 $

$ \therefore $ Fraction $ =\frac{7-4}{7}=\frac{3}{7} $

Quantitative Aptitude Ques 766

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