Quantitative Aptitude Ques 767
Question: The numerator of a fraction is 4 less than its denominator. If the numerator is decreased by 2 and the denominator is increased by 1, then the denominator becomes eight times the numerator. Find the fraction.
Options:
A) $ \frac{3}{7} $
B) $ \frac{4}{7} $
C) $ \frac{5}{7} $
D) $ \frac{6}{7} $
Show Answer
Answer:
Correct Answer: A
Solution:
- Let denominator of fraction $ =x $ Then, numerator $ =x-4 $
$ \therefore $ Fraction $ =\frac{x-4}{x} $ According to the question, $ \frac{(x-4)-2}{x+1}=\frac{1}{8} $
$ \Rightarrow $ $ x-6=\frac{x+1}{8} $
$ \Rightarrow $ $ 8x-48=x+1 $
$ \Rightarrow $ $ 8x-x=48+1 $
$ \Rightarrow $ $ 7x=49 $
$ \Rightarrow $ $ x=7 $
$ \therefore $ Fraction $ =\frac{7-4}{7}=\frac{3}{7} $
BETA
