SATHEE: Quantitative Aptitude Ques 760

Quantitative Aptitude Ques 760

Question: The area of a right angled isosceles triangle having hypotenuse $ 16\sqrt{2},cm $ is

Options:

A) $ 144cm^{2} $

B) $ 112cm^{2} $

C) $ 128cm^{2} $

D) $ 110cm^{2} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ AB=BC, $ $ \angle ABC=90{}^\circ $ Let $ AB=BC=x $ Then, by Pythagoras theorem, $ AB^{2}+BC^{2}=AC^{2} $

$ \Rightarrow $ $ x^{2}+x^{2}={{(16\sqrt{2})}^{2}} $

$ \Rightarrow $ $ 2x^{2}=16^{2}\times 2 $

$ \Rightarrow $ $ x^{2}=16^{2} $
$ \Rightarrow $ $ x=16 $

$ \therefore $ Area of triangle $ =\frac{1}{2}\times AB\times BC $ $ =\frac{1}{2}\times 16\times 16=8\times 16=128cm^{2} $

BETA

Privacy Policy

Powered by Prutor@IITK

sathee@iitk.ac.in

Media coverage of SATHEE

Play Store

App Store

The Ministry of Education has launched the SATHEE initiative in association with IIT Kanpur to provide free guidance for competitive exams. SATHEE offers a range of resources, including reference video lectures, mock tests, and other resources to support your preparation. Please note that participation in the SATHEE program does not guarantee clearing any exam or admission to any institute.

Quantitative Aptitude Ques 760

Question: The area of a right angled isosceles triangle having hypotenuse $ 16\sqrt{2},cm $ is

Options:

Answer:

Solution:

Bank Preparation

Bank Courses

NCERT Books

Important Resources

Forum