Quantitative Aptitude Ques 757

Question: By how much does $ (\sqrt{12}+\sqrt{18}) $ exceed $ (\sqrt{3}+\sqrt{2}) $ ?

Options:

A) $ \sqrt{2}-4\sqrt{3} $

B) $ \sqrt{3}+2\sqrt{2} $

C) $ 2\sqrt{3}-2\sqrt{2} $

D) $ 3(\sqrt{3}-\sqrt{2}) $

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ \sqrt{12}+\sqrt{18}=2\sqrt{3}+3\sqrt{2} $ Difference $ =(\sqrt{12}+\sqrt{18})-(\sqrt{3}+\sqrt{2}) $ $ =(2\sqrt{3}+3\sqrt{2})-(\sqrt{3}+\sqrt{2})=\sqrt{3}+2\sqrt{2} $
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