Quantitative Aptitude Ques 733

Question: If $ a=0.1039, $ then the value of $ \sqrt{4a^{2}-4a+1}+3a $ is

Options:

A) 0.1039

B) 0.2078

C) 1.1039

D) 2.1036

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ a=0.1039 $ Now, $ \sqrt{4a^{2}-4a+1}+3a=\sqrt{{{(2a-1)}^{2}}}+3a $ $ =\pm (2a-1)+3a $ $ =-2a+1+3a $ [consider $ -(2a-1) $ ] $ =a+1=0.1039+1=1.039 $
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