Quantitative Aptitude Ques 731

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.

I. $ ({x^{7/5}}\div 9)=(169\div {x^{3/5}}) $ II. $ {y^{1/4}}\times {y^{1/4}}\times 7=273\div {y^{1/2}} $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or the relationship cannot be established

Show Answer

Answer:

Correct Answer: D

Solution:

  • I. $ \frac{{x^{7/5}}}{9}=\frac{169}{{x^{3/5}}} $

$ \Rightarrow $ $ {x^{(7+3)/5)}}=169\times 9 $
$ \Rightarrow $ $ x^{2}=169\times 9 $

$ \Rightarrow $ $ x=\pm (13\times 3)=\pm 39 $ II. $ {y^{1/4}}\times {y^{1/4}}\times 7=\frac{273}{{y^{1/2}}} $

$ \Rightarrow $ $ {y^{1/2}}\times 7=\frac{273}{{y^{1/2}}} $
$ \Rightarrow $ $ y=\frac{273}{7}=39 $

$ \therefore $ $ x\le y $