Quantitative Aptitude Ques 729

Question: ABC is an equilateral triangle. P and Q are two points on AB and AC respectively such that $ PQ||BC. $ If $ PQ=5cm, $ then area of $ \Delta APQ $ is

Options:

A) $ \frac{25}{4}cm $

B) $ \frac{25}{\sqrt{3}}cm $

C) $ \frac{25\sqrt{3}}{4}cm $

D) $ 25\sqrt{3},cm $

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Answer:

Correct Answer: C

Solution:

  • Since, $ PQ||BC $

$ \therefore $ $ \angle APQ=\angle AQP=60{}^\circ $

$ \therefore $ $ \Delta APQ $ is an equilateral triangle.
So, $ \Delta APQ,\sim ,\Delta ABC $

$ \therefore ,Area,of,(\Delta APQ) $ $ =\frac{\sqrt{3}}{4}{{(PQ)}^{2}}=\frac{\sqrt{3}}{4}\times 25=\frac{25\sqrt{3}}{4}cm^{2} $