Quantitative Aptitude Ques 719
Question: Acid and water are mixed in a vessel A in the ratio of 5: 2 and in the vessel B in the ratio of 8: 5. In what proportion should quantities be taken out from the two vessels, so as to form a mixture in which the acid and water will be in the ratio of 9: 4?
Options:
A) 7 : 2
B) 2 : 7
C) 7 : 4
D) 2 : 3
Show Answer
Answer:
Correct Answer: A
Solution:
- Quantity of acid in vessel A $ =\frac{5}{7} $ Quantity of acid in vessel B $ =\frac{8}{13} $ Quantity of acid in vessel C $ =\frac{9}{13} $ By mixture method,
$ \therefore $ Required ratio $ =\frac{1}{13}:\frac{2}{91}=7:2 $
BETA
