Quantitative Aptitude Ques 719

Question: Acid and water are mixed in a vessel A in the ratio of 5: 2 and in the vessel B in the ratio of 8: 5. In what proportion should quantities be taken out from the two vessels, so as to form a mixture in which the acid and water will be in the ratio of 9: 4?

Options:

A) 7 : 2

B) 2 : 7

C) 7 : 4

D) 2 : 3

Show Answer

Answer:

Correct Answer: A

Solution:

  • Quantity of acid in vessel A $ =\frac{5}{7} $ Quantity of acid in vessel B $ =\frac{8}{13} $ Quantity of acid in vessel C $ =\frac{9}{13} $ By mixture method,

$ \therefore $ Required ratio $ =\frac{1}{13}:\frac{2}{91}=7:2 $

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