Options:
A) 420 m
B) 500 m
C) 300 m
D) 250 m
Show Answer
Answer:
Correct Answer: C
Solution:
- Given, speed of train
$ =60,km/h=60\times \frac{5}{18}m/s $
$ =\frac{50}{3}m/s $ and time = 30 s
Let length of platform = x m
$ \because $ Distance = Time $ \times $ Speed
$ \Rightarrow $ $ 200+x=\frac{50}{3}\times 30 $
$ \Rightarrow $ $ 200+x=500 $
$ \therefore $ $ x=300,m $