Options:
A) $ 20m $
B) $ 30m $
C) $ 20\sqrt{3} $
D) $ 30\sqrt{3} $
Show Answer
Answer:
Correct Answer: C
Solution:
- Let AB be the light house with top AB = 20 m
In $ \Delta ABC, $ $ \tan 60{}^\circ =\frac{BC}{AB} $
$ \Rightarrow $ $ \sqrt{3}=\frac{BC}{20} $
$ \Rightarrow $ $ BC=20\sqrt{3}m $