Quantitative Aptitude Ques 65

Question: If $ \frac{p^{2}}{q^{2}}+\frac{q^{2}}{p^{2}}=1, $ then what is the value of $ (p^{6}+q^{6})? $

Options:

A) 0

B) 1

C) 2

D) 3

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ \frac{p^{2}}{q^{2}}=\frac{q^{2}}{p^{2}}=1 $
    $ \Rightarrow $ $ p^{4}+q^{4}=p^{2}q^{2} $

$ \Rightarrow $ $ p^{4}+q^{4}-p^{2}q^{2}=0 $ Now, $ p^{6}+q^{6}=(p^{2}+q^{2})(p^{4}+q^{4}-p^{2}q^{2}) $ $ =(p^{2}+q^{2})\cdot (0)=0 $