Quantitative Aptitude Ques 633
Options:
A) 4! = 24
B) $ 3!,\times ,4! $
C) 836
D) 7!
E) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- Number of different words which can be formed $ =\frac{7!}{3!} $
Consonants (MXMM)
Number of words in which consonants occur together
$ =\frac{4!}{3!} $
Number of words in which consonants do not occur together $ =\frac{7!}{3!}-\frac{4!}{3!}=\frac{4!}{3!}(7\times 6\times 5-1)=836 $