SATHEE: Quantitative Aptitude Ques 625

Quantitative Aptitude Ques 625

Question: If $ 2x=\sec A $ and $ \frac{2}{x}=\tan A, $ then $ 2( x^{2}-\frac{1}{x^{2}} ) $ is equal to

Options:

A) $ \frac{1}{2} $

B) $ \frac{1}{4} $

C) $ \frac{1}{8} $

D) $ \frac{1}{16} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ ( 2x+\frac{2}{x} )( 2x-\frac{2}{x} )=(\sec A+\tan A)(\sec A-\tan A) $
$ \Rightarrow $ $ 4( x^{2}-\frac{1}{x^{2}} )=( \frac{1+\sin A}{\cos A} )( \frac{1-\sin A}{\cos A} )=\frac{{{\cos }^{2}}A}{{{\cos }^{2}}A}=1 $

$ \Rightarrow $ $ 2( x^{2}-\frac{1}{x^{2}} )=\frac{1}{2} $

BETA

Privacy Policy

Powered by Prutor@IITK

sathee@iitk.ac.in

Media coverage of SATHEE

Play Store

App Store

The Ministry of Education has launched the SATHEE initiative in association with IIT Kanpur to provide free guidance for competitive exams. SATHEE offers a range of resources, including reference video lectures, mock tests, and other resources to support your preparation. Please note that participation in the SATHEE program does not guarantee clearing any exam or admission to any institute.

Quantitative Aptitude Ques 625

Question: If $ 2x=\sec A $ and $ \frac{2}{x}=\tan A, $ then $ 2( x^{2}-\frac{1}{x^{2}} ) $ is equal to

Options:

Answer:

Solution:

Bank Preparation

Bank Courses

NCERT Books

Important Resources

Forum