Question: Two pipes P and Q can fill a cistern in 12 and 15 min, respectively. Both are opened together but at the end of 3 min, P is turned off. In how many more minutes will Q fill the cistern?
Options:
A) 7 min
B) $ 7\frac{1}{2}\min $
C) 8 min
D) $ 8\frac{1}{4}\min $
Show Answer
Answer:
Correct Answer: D
Solution:
- 1 min work of $ P=\frac{1}{12} $
$ \Rightarrow $ 1min work of $ Q=\frac{1}{15} $
1 min work of P and Q both $ =\frac{1}{12}+\frac{1}{15}=\frac{3}{20} $
$ \Rightarrow $ 3 min work of P and $ Q=\frac{9}{20} $
$ \therefore $ Remaining work $ =1-\frac{9}{20}=\frac{11}{20} $
Time taken by $ Q=\frac{11}{20}\times 15=\frac{33}{4}=8\frac{1}{4}\min $