Quantitative Aptitude Ques 584

Question: Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer.

I. $ 3x^{2}+11x+10=0 $ II. $ 2y^{2}+13y+21=0 $

Options:

A) If $ x\ge y $

B) If $ x\le y $

C) If $ x>y $

D) If $ x<y $

E) If relationship between x and y cannot be established

Show Answer

Answer:

Correct Answer: C

Solution:

  • I. $ 3x^{2}+11x+10=0 $

$ \Rightarrow $ $ 3x^{2}+6x+5x+10=0 $

$ \Rightarrow $ $ 3x,(x+2)+5,(x+2)=0 $

$ \Rightarrow $ $ x=-\frac{5}{3}, $ $ -,2 $ II. $ 2y^{2}+13y+21=0 $

$ \Rightarrow $ $ 2y^{2}+6y+7y+21=0 $

$ \Rightarrow $ $ 2y,(y+3)+7,(y+3)=0 $

$ \Rightarrow $ $ y=-,3, $ $ \frac{-7}{2} $

$ \therefore $ $ x>y $