Quantitative Aptitude Ques 582

Question: Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer.

I. $ 4x^{2}+17x+15=0 $ II. $ 3y^{2}+19y+28=0 $

Options:

A) If $ x\ge y $

B) If $ x\le y $

C) If $ x>y $

D) If $ x<y $

E) If relationship between x and y cannot be established

Show Answer

Answer:

Correct Answer: C

Solution:

  • I. $ 4x^{2}+17x+15=0 $

$ \Rightarrow $ $ 4x^{2}+12x+5x+15=0 $

$ \Rightarrow $ $ 4x,(x+3)+5,(x+3)=0 $

$ \Rightarrow $ $ x=-,3, $ $ \frac{-,5}{4} $ II. $ 3y^{2}+19y+28=0 $

$ \Rightarrow $ $ 3y^{2}+12y+7y+28=0 $

$ \Rightarrow $ $ 3y,(y+4)+7,(y+4)=0 $

$ \Rightarrow $ $ y=-,4, $ $ \frac{-7}{3} $

$ \therefore $ $ x>y $