A) $ 140\sqrt{2}, $ 198
B) 234, 216
C) 216, 234
D) 198, $ 140\sqrt{2} $
Correct Answer: D
$ \Rightarrow $ $ x+\frac{1}{x}=6 $ On cubing both sides, we get $ x^{3}+\frac{1}{x^{3}}+3( x+\frac{1}{x} )x\times \frac{1}{x}=6^{3} $
$ \Rightarrow $ $ x^{3}+\frac{1}{x^{3}}+3,(6)=216 $
$ \Rightarrow $ $ x^{3}+\frac{1}{x^{3}}=216-18=198 $ Similarly, $ x^{3}-\frac{1}{x^{3}}=140\sqrt{2} $