Quantitative Aptitude Ques 572

Question: There are three pipes in a tank, first pipe can fill $ \frac{1}{2} $ part of the tank in 1 h, second pipe can fill $ \frac{1}{3} $ part of tank in 1 h and third pipe is used to make the tank empty. All three pipes are opened together, then only $ \frac{7}{12} $ part of tank is filled in one hour. In what time can the third pipe emptied the whole tank?

Options:

A) 3 h

B) 4 h

C) 5 h

D) 6 h

Show Answer

Answer:

Correct Answer: B

Solution:

  • 1 h work of first pipe $ =\frac{1}{2} $ 1 h work of second pipe $ =\frac{1}{3} $

$ \therefore $ 1 h work of third pipe $ =\frac{7}{12}-\frac{1}{3}-\frac{1}{2}=-\frac{3}{12}=-\frac{1}{4} $ Hence, third pipe emptied the tank in 4 h.

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