Question: A bus started its journey from Ramgarh and reached Devgarh in 44 min at its average speed of 50 km/h. If the average speed of the bus is increased by 5 km/h, then how much time will it take to cover the same distance?
[Corporation Bank (PO) 2010]
Options:
A) 40 mm
B) 38 min
C) 36 min
D) 31 min
E) 49 min
Show Answer
Answer:
Correct Answer: A
Solution:
- Average speed of bus = 50 km/h
and time taken $ =44\min =\frac{44}{60}h $
Distance between Ramgarh and Devgarh
$ =50\times \frac{44}{60}km $
Now, new speed = 55 km/h
$ \therefore $ Required time =
$ =\frac{50\times 44}{60\times 55}\times 60\min =40\min $