Question: The points (2, 2), (6, 3) and (4, 11) are the vertices of
Options:
A) an equilateral
B) a right angled triangle
C) an isosceles triangle
D) a scalene triangle
Show Answer
Answer:
Correct Answer: D
Solution:
- $ AC=\sqrt{{{(11-2)}^{2}}+{{(4-2)}^{2}}} $
$ =\sqrt{81+4}=\sqrt{85} $
$ BC=\sqrt{{{(11-3)}^{2}}+{{(4-6)}^{2}}} $
$ =\sqrt{8^{2}+2^{2}}=\sqrt{64+4}=\sqrt{68} $
$ AB=\sqrt{{{(3-2)}^{2}}+{{(6-2)}^{2}}} $
$ =\sqrt{1+16}=\sqrt{17} $
$ \therefore $ $ AC\ne BC\ne AB $
Hence, the points are the vertices of a scalene triangle.