SATHEE: Quantitative Aptitude Ques 560

Quantitative Aptitude Ques 560

Question: A sells an item at 20% profit to B. B sells it to C at 10% profit. C sells it to D at Rs. 16 profit. Difference between the cost price of D and cost price of A was Rs. 500. How much did B pay to A for the item?

Options:

A) Rs. 1240

B) Rs. 1815

C) Rs. 1440

D) Rs. 1450

E) Rs. 1400

Show Answer

Answer:

Correct Answer: B

Solution:

Let cost price of A be x. Selling price for $ A=x+\frac{20}{100}x $ $ =\frac{120x}{100} $ = cost price for B Selling price for $ B=\frac{120x}{100}+( \frac{10}{100} )( \frac{120x}{100} ) $ $ =\frac{132x}{100}=CP,for,C $ Selling price for $ C=\frac{132x}{100}+16=CP,for,D $ According to the question, $ ( \frac{132x}{100}+16 )-(x)=500 $

$ \Rightarrow $ $ \frac{132x+1600-100x}{100}=500 $

$ \Rightarrow $ $ 32x=500\times 100-1600 $

$ \Rightarrow $ $ x=\frac{50000-1600}{32}=\frac{48400}{32}=\frac{12100}{8} $

$ \therefore $ Cost price for $ B=\frac{120\times x}{100}=\frac{120}{100}\times \frac{12100}{8}=Rs.,1815 $

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Quantitative Aptitude Ques 561

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