Quantitative Aptitude Ques 556

Question: The length of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, then the distance of the other chord from the centre is

Options:

A) 5 cm

B) 6 cm

C) 4 cm

D) 3 cm

Show Answer

Answer:

Correct Answer: D

Solution:

  • Length of smaller chord be 6 cm.

$ \therefore $ $ MB=3,cm, $ and $ OM=4,cm $

$ \therefore $ In $ \Delta OMB, $ using Pythagoras theorem $ OB^{2}=OM^{2}+MB^{2} $ $ =9+16=25 $

$ \Rightarrow $ $ OB=5,cm $ [radius of the circle]

$ \therefore $ $ OD=5,cm $ and $ ND=\frac{CD}{2}=\frac{8}{2}=4,cm $

$ \therefore $ In $ \Delta OND, $ using Pythagoras theorem $ ON^{2}=OD^{2}-ND^{2} $ $ =25-16=9 $

$ \Rightarrow $ $ ON=3,cm $ Distance = 3 cm