Quantitative Aptitude Ques 530

Question: How many even 3-digit numbers can be formed from the digits 1, 2, 5, 6 and 9 without repeating any of the digits?

Options:

A) 120

B) 48

C) 40

D) 24

Show Answer

Answer:

Correct Answer: D

Solution:

  • [d] for digit to be even, units digit will be even. From the given digits, only 2 and 6 satisfy condition.
    $ \therefore $ Units place will always be 2 or 6. Then, rest two places will be occupied by any of the four digits i.e. $ {}^{4}P _2=\frac{4!}{(4-2)!}=\frac{4\times 3\times 2}{2}=12 $
    $ \therefore $ Total even numbers formed by digits 1, 2, 5 and 6 $ =12\times 2=24 $
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