Quantitative Aptitude Ques 528
Question: The population of a state in the year was 93771. If the rate of increase was 8% and 15% respectively from the previous 2 yr before 2013, what was the population in the year 2011? [NICL (AO) 2014]
Options:
A) 55650
B) 49550
C) 75500
D) 84500
E) 65200
Show Answer
Answer:
Correct Answer: C
Solution:
- [c] Let population in year 2011 = x
$ \therefore $ Population in year 2012 $ =x+\frac{x\times 8}{100}=\frac{27x}{25} $ Now, population in year 2013 $ =\frac{27x}{25}+\frac{27x}{25}\times \frac{15}{100}=\frac{621x}{500} $ According to the question, $ =\frac{621x}{500}=93771 $
$ \Rightarrow $ $ x=\frac{93771\times 500}{621}=151\times 500 $
$ \Rightarrow $ $ x=75500 $
BETA
