SATHEE: Quantitative Aptitude Ques 515

Quantitative Aptitude Ques 515

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.

I. $ x^{2}-10x+24=0 $ II. $ y^{2}-9y+20=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) $ x\le y $

E) If $ x=y $ or the relationship cannot be established

Show Answer

Answer:

Correct Answer: B

Solution:

[b] I. $ x^{2}-10x+24=0 $

$ \Rightarrow $ $ x^{2}-6x-4x+24=0 $

$ \Rightarrow $ $ x,(x-6)-4,(x-6)=0 $

$ \Rightarrow $ $ (x-4)(x-6)=0 $

$ \Rightarrow $ $ x=4, $ 6 II. $ y^{2}-9y+20=0 $
$ \Rightarrow $ $ y^{2}-5y-4y+20=0 $

$ \Rightarrow $ $ y,(y-5)-4,(y-5)=0 $

$ \Rightarrow $ $ (y-4)(y-5)=0 $

$ \Rightarrow $ $ y=4, $ $ y=5 $

$ \therefore $ $ x\ge y $

Quantitative Aptitude Ques 514

Quantitative Aptitude Ques 516

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