SATHEE: Quantitative Aptitude Ques 514

Quantitative Aptitude Ques 514

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.

I. $ x^{2}+5x+6=0 $ II. $ y^{2}+3y+2=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) $ x\le y $

E) If $ x=y $ or the relationship cannot be established

Show Answer

Answer:

Correct Answer: D

Solution:

[d] I. $ x^{2}+5x+6=0 $

$ \Rightarrow $ $ x^{2}+2x+3x+6=0 $

$ \Rightarrow $ $ x(x+2)+3(x+2)=0 $

$ \Rightarrow $ $ (x+2)(x+3)=0 $

$ \Rightarrow $ $ x=-,2, $ $ -3 $ II. $ y^{2}+3y+2=0 $

$ \Rightarrow $ $ y^{2}+2y+y+2=0 $

$ \Rightarrow $ $ y,(y+2)+1,(y+2)=0 $

$ \Rightarrow $ $ (y+1),(y+2)=0 $

$ \Rightarrow $ $ y=-1, $ $ y=-,2 $

$ \therefore $ $ x\le y $

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