Quantitative Aptitude Ques 514
Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.
I. $ x^{2}+5x+6=0 $ II. $ y^{2}+3y+2=0 $
Options:
A) If $ x>y $
B) If $ x\ge y $
C) If $ x<y $
D) $ x\le y $
E) If $ x=y $ or the relationship cannot be established
Show Answer
Answer:
Correct Answer: D
Solution:
- [d] I. $ x^{2}+5x+6=0 $
$ \Rightarrow $ $ x^{2}+2x+3x+6=0 $
$ \Rightarrow $ $ x(x+2)+3(x+2)=0 $
$ \Rightarrow $ $ (x+2)(x+3)=0 $
$ \Rightarrow $ $ x=-,2, $ $ -3 $ II. $ y^{2}+3y+2=0 $
$ \Rightarrow $ $ y^{2}+2y+y+2=0 $
$ \Rightarrow $ $ y,(y+2)+1,(y+2)=0 $
$ \Rightarrow $ $ (y+1),(y+2)=0 $
$ \Rightarrow $ $ y=-1, $ $ y=-,2 $
$ \therefore $ $ x\le y $
BETA
