Quantitative Aptitude Ques 497
Question: Two pipes A and B alone can fill the tank in 6 h and 4 h, respectively. If they work alternatively for one hour each and first pipe A works, then time taken by them to fill the tank is
Options:
A) 4 h
B) 5 h
C) $ 4\frac{1}{2},h $
D) $ 5\frac{1}{2},h $
Show Answer
Answer:
Correct Answer: B
Solution:
- 1 h work of pipe $ A=\frac{1}{6} $ and 1 h work of pipes $ B=\frac{1}{4} $
$ \therefore $ 2 h work of both pipes $ =\frac{1}{6}+\frac{1}{4}=\frac{5}{12} $ 4 h work of both pipes $ =\frac{5}{12}\times 2=\frac{5}{6} $
$ \therefore $ Remaining work $ =1-\frac{5}{6}=\frac{1}{6} $ Now, it is turn of pipe A and so the remaining work will be completed in 1 h. Total time taken to fill the tank $ =4+1=5,h $
BETA
