Quantitative Aptitude Ques 497

Question: Two pipes A and B alone can fill the tank in 6 h and 4 h, respectively. If they work alternatively for one hour each and first pipe A works, then time taken by them to fill the tank is

Options:

A) 4 h

B) 5 h

C) $ 4\frac{1}{2},h $

D) $ 5\frac{1}{2},h $

Show Answer

Answer:

Correct Answer: B

Solution:

  • 1 h work of pipe $ A=\frac{1}{6} $ and 1 h work of pipes $ B=\frac{1}{4} $

$ \therefore $ 2 h work of both pipes $ =\frac{1}{6}+\frac{1}{4}=\frac{5}{12} $ 4 h work of both pipes $ =\frac{5}{12}\times 2=\frac{5}{6} $

$ \therefore $ Remaining work $ =1-\frac{5}{6}=\frac{1}{6} $ Now, it is turn of pipe A and so the remaining work will be completed in 1 h. Total time taken to fill the tank $ =4+1=5,h $