A) 4 h
B) 5 h
C) $ 4\frac{1}{2},h $
D) $ 5\frac{1}{2},h $
Correct Answer: B
$ \therefore $ 2 h work of both pipes $ =\frac{1}{6}+\frac{1}{4}=\frac{5}{12} $ 4 h work of both pipes $ =\frac{5}{12}\times 2=\frac{5}{6} $
$ \therefore $ Remaining work $ =1-\frac{5}{6}=\frac{1}{6} $ Now, it is turn of pipe A and so the remaining work will be completed in 1 h. Total time taken to fill the tank $ =4+1=5,h $