Question: A student goes to school at the rate of $ 2\frac{1}{2},km/h $ and reaches 6 min late. If he travels at the speed of 3 km/h, he is 10 min early The distance (in km) between the school and his house is
Options:
A) 5
B) 4
C) 3
D) 1
Show Answer
Answer:
Correct Answer: B
Solution:
- Let $ x=\frac{5}{2}, $ $ y=3, $ $ t _1=6, $ $ t _2=10 $
$ \therefore $ Required distance $ =xy,\frac{(t _1+t _2)}{y-x} $
$ =\frac{3\times \frac{5}{2}\times (6+10)}{3-5/2} $
$ =\frac{15}{2}\times \frac{16}{60}\times \frac{2}{1}=4,km $