Quantitative Aptitude Ques 475

Question: A student goes to school at the rate of $ 2\frac{1}{2},km/h $ and reaches 6 min late. If he travels at the speed of 3 km/h, he is 10 min early The distance (in km) between the school and his house is

Options:

A) 5

B) 4

C) 3

D) 1

Show Answer

Answer:

Correct Answer: B

Solution:

  • Let $ x=\frac{5}{2}, $ $ y=3, $ $ t _1=6, $ $ t _2=10 $

$ \therefore $ Required distance $ =xy,\frac{(t _1+t _2)}{y-x} $ $ =\frac{3\times \frac{5}{2}\times (6+10)}{3-5/2} $ $ =\frac{15}{2}\times \frac{16}{60}\times \frac{2}{1}=4,km $