Question: The least number which when divided by 24, 32 and 36 leaves the remainders 19, 27 and 31 respectively, is
Options:
A) 283
B) 288
C) 293
D) 299
Show Answer
Answer:
Correct Answer: A
Solution:
- Here, $ 24-19=5 $
$ 32-27=5 $
and $ 36-31=5 $
LCM of (24, 32, 36)
$ \therefore $ $ LCM=2\times 2\times 2\times 3\times 4\times 3=288 $
$ \therefore $ Required number $ =288-5=283 $