Quantitative Aptitude Ques 456

Question: Directions: In each of the following questions there are two equations. You have to solve both equations and give answer. [SBI (PO) 2015]

I. $ x^{2}+5x+6=0 $ II. $ 2y^{2}+7y+6=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ of relation cannot be established

Show Answer

Answer:

Correct Answer: D

Solution:

  • I. $ x^{2}+5x+6=0 $

$ \Rightarrow $ $ x^{2}+2x+3x+6=0 $

$ \Rightarrow $ $ (x+2)(x+3)=0 $

$ \Rightarrow $ $ x=-,2, $ $ x=-,3 $ II. $ 2y^{2}+7y+6=0 $

$ \Rightarrow $ $ 2y^{2}+4y+3y+6=0 $

$ \Rightarrow $ $ 2y,(y+2)+3,(y+2)=0 $

$ \Rightarrow $ $ (y+2)(2y+3)=0 $

$ \Rightarrow $ $ y=-,2, $ $ \frac{-,3}{2} $

$ \therefore $ $ x\le y $

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