Quantitative Aptitude Ques 456
Question: Directions: In each of the following questions there are two equations. You have to solve both equations and give answer. [SBI (PO) 2015]
I. $ x^{2}+5x+6=0 $ II. $ 2y^{2}+7y+6=0 $
Options:
A) If $ x>y $
B) If $ x\ge y $
C) If $ x<y $
D) If $ x\le y $
E) If $ x=y $ of relation cannot be established
Show Answer
Answer:
Correct Answer: D
Solution:
- I. $ x^{2}+5x+6=0 $
$ \Rightarrow $ $ x^{2}+2x+3x+6=0 $
$ \Rightarrow $ $ (x+2)(x+3)=0 $
$ \Rightarrow $ $ x=-,2, $ $ x=-,3 $ II. $ 2y^{2}+7y+6=0 $
$ \Rightarrow $ $ 2y^{2}+4y+3y+6=0 $
$ \Rightarrow $ $ 2y,(y+2)+3,(y+2)=0 $
$ \Rightarrow $ $ (y+2)(2y+3)=0 $
$ \Rightarrow $ $ y=-,2, $ $ \frac{-,3}{2} $
$ \therefore $ $ x\le y $
BETA
